7x^2-3x=37

Solution for 7x^2-3x=37 equation:

7x^2-3x=37

We move all terms to the left:

7x^2-3x-(37)=0

a = 7; b = -3; c = -37;
Δ = b2-4ac
Δ = -32-4·7·(-37)
Δ = 1045
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{1045}}{2*7}=\frac{3-\sqrt{1045}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{1045}}{2*7}=\frac{3+\sqrt{1045}}{14}
$